题干

如图,已知AD∥BC,∠PAB的平分线与∠CBA的平分线相交于E,CE的连线交AP于D.求证:AD+BC=AB.

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答案(点此获取答案解析)

证明:在AB上截取AF=AD,

∵AE平分∠PAB,

∴∠DAE=∠FAE,

在△DAE和△FAE中,

{AD=AF

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