用秦九韶算法写出求f(x)=1+x+0.5x2+0.16667x3+0.04167x4+0.00833x5在x=﹣0.2时的值的过程.
解:先把函数整理成
f(x)=((((0.00833x+0.04167)x+0.16667)x+0.5)x+1)x+1,
按照从内向外的顺序依次进行.
x=﹣0.2
a5=0.00833 V0=a5=0.00833
a4=0.04167 V1=V0x+a4=0.04
a
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