如图,△ABC中,∠ACB=90°,延长AC到D,使得CD=CB,过点D作DE⊥AB于点E,交BC于F.求证:AB=DF.
证明:∵DE⊥AB,
∴∠DEA=90°,
∵∠ACB=90°,
∴∠DEA=∠ACB,
∴∠D=∠B,
在△DCF和△ACB中,
∠DCB=<
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