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某算法的部分流程图如图所示。执行这部分流程后,变量a的值为(    )
A.1B.2
C.3D.4
上一题 下一题 0.99难度 选择题 更新时间:2019-05-06 05:21:14

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同类题2

小李编写一个统计学生选考科目的 VB 程序,算法的基本思想是:检查每位学生选课组合的编码是否有效,对有效选择结果进行科目统计,根据各科占有效人数的百分率求出各科排名。程序运行时,单击“显示”按钮 Command1,学生选课数据显示在列表框 List1 中,各科编号及对应科目名称显示在列表框 List2 中,单击“统计”按钮 Command2,选课结果按各科百分率由高到低显示在列表框 List3 中,程序运行结果如图所示。

现上述功能的 VB 程序如下,请回答下列问题:
(1)学生选课的编码数据存储在数据表中,其字段名为__________________。
(2)请在划线处填入合适的代码。
Dim ach(1 To 500) As String  '存储各学生选课编码
Dim bno(1 To 10) As Integer '存储各科目编号
Dim bname(1 To 10) As String '存储各科目名称
Dim bnum(1 To 10) As Integer  '存储各科目被选次数
Dim bmc(1 To 10) As Integer '存储各科目被选的名次
Dim n As Integer, num As Integer
Private Sub Command1_Click()
Dim i As Integer, km As String
km = "物理化学生物政治历史地理技术"
Dim cn As New ADODB. Connection, rs As New
ADODB. Recordset, sql As String
cn. Open "provider=Microsoft. Jet. oledb. 4. 0;Data Source =" + App. Path + " \students. mdb"
rs. Open "select ∗ from choose", cn
Do While Not rs. EOF
n = n + 1 : ach(n) = rs. Fields("subject") : rs. MoveNext
Loop
rs. Close: cn. Close
Set rs = Nothing
Set cn = Nothing
For i = 1 To 7
bno(i) = i: bname(i) = Mid(km, (i - 1) ∗2 + 1, 2)
List2. AddItem Str (bno (i)) + " - - -" +bname(i)
Next i
End Sub
Private Sub Command2_Click()
Dim i As Integer, j As Integer, k As Integer
Dim c As String, per As Integer
For i = 1 To n
If check(ach(i)) =True Then
For j = 1 To 3
c = Mid(ach(i), j, 1)
bnum(Val(c)) = _________
Next j
num = num + 1
End If
Next i
i = 1
Do While i <= 7  '该循环得到各学科被选人数的名次
bmc(i) = 1
For j = 1 To 7
If bnum(j) > bnum(i) Then __________
Next j
i = i + 1
Loop
For i = 1 To 7
For j = 1 To 7
If _________Then
per = Int(bnum(j) ∗ 100 / num ∗ 100)/ 100
List3. AddItem Str(bno(j)) + "---" +bname(j) + "---" + Str(per) + "%"
End If
Next j
Next i
End Sub
Function check(s As String) As Boolean
'代码略,若学生选科代码有效,函数返回 True,否则返回 False
End Function

同类题3

(加试题)最大回文子串。回文字符串是具有回文特性的字符串:即该字符串从左向右读, 与从右向左读都一样.如:凤落梧桐梧落凤,abcba 等。“最大回文子串”是指一个字符串中长 度最大的回文字符串,其基本算法思想如下:
(1)每个回文都有一个“中心”,当回文字符数为奇数时,中间的那个字符就是回文中心;但是当回文的字符数为偶数时,回文的中心是最中间的那两个字符,且这两个字符相同。
(2)对任意一个字符或者相同的两个连续字符,我们都可以假设它为回文的“中心”,向它的 左右两边扩展出尽可能长的回文。对于每种假设,我们都能得到一个回文,而最长回文必定由 其中的某个假设中得到!
现编写一个 V
A.程序,在 Text1 中输入一串字符,单击“统计”按钮,在 Text2 中显示该字 符串中的最大的回文子串(长度相同时,输出最左边的子串)。请回答下列问题:
(1)当 Text1 中输入“123321344332423112113123”时,则输出的结果为_________。
(2)请在划线处填入合适的代码。
Dim n As Integer
Dim a(0 To 100) As String Private Sub Command1 Click() Dim s As String
Dim left As Integer, right As Integer, i As Integer
Dim max As Integer, m As Integer, b1 As Integer
'变量 b1 用于记录回文子串的左端起点 Text2.Text = ""
s = Text1.Text n = Len(s)
For i = 1 To n

a(i) = Mid(s, i, 1) Next i

max = 0: left = 0: right = 0
For i = 1 To n left = i
right = i
m = longest(left, right) If m > max Then
b1 = i - m \ 2 max = m
End If left = i
right = i + 1
If a(left) = a(right) Then
m = longest(left, right) + 1
If m > max Then
①________
max = m
End If
End If
Next i
For i = b1 To ②________

Text2.Text = Text2.Text + a(i) Next i

End Sub
Function longest(left As Integer, right As Integer) As Integer
Dim p As Integer p = 1
Do While left > 1 And right < n And ③________
left = left - 1 right = right + 1 p = p + 2
Loop
longest = p
End Function