A.![]() 证明:∵DG⊥BC,AC⊥BC(已知) ∴∠DGB=∠ACB=90°(________________________) ∴DG//AC(____________________________) ∴∠2=∠_____(_____________________________) ∵∠1=∠2(_______________) ∴∠1=∠_____(等量代换) ∴EF//CD(_______________________) ∴∠AEF=∠______(____________________) ∵EF⊥AB ∴∠AEF=90°(________________________) ∴∠ADC=90°(等量代换) 即CD⊥AB(垂直的定义) |