(Ⅰ)求数列{an}的通项公式;
(Ⅱ)设bn=anlog 12 an,求数列{bn}的前n项和Sn.
∵a3+2是a2,a4的等差中项
∴2(a3+2)=a2+a4
代入a2+a3+a4=28,得a3=8
∴a2+a4<
3×____=____×____
---Let me ________it.