先化简,再求值:[(x﹣y)2+(x+y)(x﹣y)]÷2x,其中x=3,y=1.
解:原式=(x2﹣2xy+y2+x2﹣y2)÷2x
=(2x2﹣2xy)÷2x
=x﹣y,
则当x=3,y=1时,原式=3﹣1=2.
和王兵打招呼应该说: