已知M=x2+3x﹣a,N=﹣x,P=x3+3x2+5,且M•N+P的值与x的取值无关,求a的值.
解:M•N+P=(x2+3x﹣a)•(﹣x)+(x3+3x2+5)
=﹣x3﹣3x2+ax+x3+3x2+5
=ax+5
∵M•N+P的值与x的取值无关,
∴a=0.