如图，O是长方体ABCD﹣A1B1C1D1底面对角线AC与BD的交点，求证：B1O∥平面A1C1D．_刷题宝

题干

如图，O是长方体ABCD﹣A₁B₁C₁D₁底面对角线AC与BD的交点，求证：B₁O∥平面A₁C₁D．

上一题下一题 0.0难度选择题更新时间:2018-06-19 01:04:30

答案(点此获取答案解析）

证明：连A₁C₁交B₁D₁于O₁，连DO₁，

∵O₁B₁∥DO，O₁B₁=DO，

∴O₁B₁OD为平行四边形，

∴B₁O∥O₁D

∵BO₁

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