如图所示,实线是一簇未标明方向的由点电荷Q产生的电场线,若带电粒子q(|Q|>>|q|)由a运动到b,电场力做正功.已知粒子在a、b两点所受电场力分别为Fa、Fb,则下列判断正确的是( )
A:若Q为正电荷,则q带正电,Fa>Fb
B:若Q为正电荷,则q带正电,Fa<Fb
C:若Q为负电荷,则q带正电,Fa>Fb
D:若Q为负电荷,则q带正电,Fa<Fb
— Are there any flowers _______ the tree.— No. But there are many birds _________ it.