GA×AO=(GB+F)×OB,
即:200N×AO=(80N+F)×OB,
已知:AO:OB=3:2,解得:
F=220N;
答:加在配重下面绳端的竖直向下的拉力F是220N
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方程x+y+3z=22的正整数解的组数是____ .