已知F₁，F₂为双曲线 $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\left(a＞0,b＞0\right)$ 的左、右焦点，过点F₂作此双曲线一条渐近线的垂线，垂足为M，且满足| $\overrightarrow{M{F}_1}$ |=3| $\overrightarrow{M{F}_2}$ |，则此双曲线的离心率是（  ）

Jack: Hi, Amy. What do you have on Mondays?

Amy: I have ____ class and art.

Jack: Can you ____?

Amy: Yes, I can.

Jack: Can you ____?

Amy: No, I can't.

Jack: What do you do on the weekend?

Amy: I often read ____

Jack: Do you often play ____?

Amy: No, I don't.