A:过敏反应增强
B:营养物质得不到及时补充
C:T细胞作用减弱
D:非特异性免疫功能下降
40+2= 70+3= 10+8= 80+0= 40+5=
3+90= 10+6= 30+2= 50+9= 9+80=
1+10= 8+80= 20+1= 20+3=
0+10= 18–8= 86–6= 68–8= 65–5= 55–50= 93–90= 35–5= 45–40= 75–70= 38–30= 27–20=
57–7= 37–7= 100–30= 66–6=
43–3= 94–90= 34–30= 89–9= 51–1=
— I'm hungry. ________ there any bread in the fridge, Mum?
— None, but we have cakes. Would you like to have one?
已知a、b、c、d是某细菌DNA片段上的4个基因,右图中W表示野生型,①、②、③分别表示三种缺失不同基因的突变体,虚线表示所缺失的基因。若分别检测野生型和各种突变体中某种酶的活性,发现仅在野生型和突变体①中该酶有活性,则编码该酶的基因是