(1)用辗转相除法求840与1764的最大公约数.
(2)用更相减损术求561与255的最大公约数.
解:(1)1746=840×2+84,
840=84×10+0,
所以840与1764的最大公约数为84.
(2)561﹣255=306,
306﹣255=51,
255﹣51=204,
204﹣51=153,
153﹣51=102,
102﹣51=51
所以459与357的最大公约数为51.
补全下列对话。
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