如图,一带电液滴在重力和匀强电场对它的作用力作用下,从静止开始由b沿直线运动到d,且bd与竖直方向所夹的锐角为45°,则下列结论不正确的是 ( )
A:此液滴带负电
B:液滴的加速度等于2g
C:合外力对液滴做正功
D:液滴的电势能增加
The teachers encourage their students to the problems by themselves, and in this way students can enjoy success.
反应Ⅰ:Fe2O3(s)+ 3H2(g)=2Fe(s)+3H2O(g) ΔH1= +89 .6kJ /mol
反应Ⅱ:4Fe2O3(s)+Fe(s)=3Fe3O4(s) ΔH2=+2833.4kJ/mol
反应Ⅲ:Fe(s)+2HCl(g) ⇌ FeCl2(l)+H2(g) ΔH3