A:质量亏损为Δm=235.043 9u+1.008 7u-89.907 7 u-135.907 2u
B:质量亏损为Δm=(235.043 9+1.008 7-89.907 7-135.907 2-10×1.0087)u
C:释放的总能量为ΔE=(235.043 9+1.008 7-89.907 7-135.907 2-10×1.0087)×(3×108)2J
D:释放的总能量为ΔE=(235.043 9+1.008 7-89.907 7-135.907 2-10×1.0087)×931.5MeV