王红同学在计算(2+1)(22+1)(24+1)时,将积式乘以(2﹣1)得:
解:原式=(2﹣1)(2+1)(22+1)(24+1)
=(22﹣1)(22+1)(24+1)
=(24﹣1)(24+1)
=28﹣1
根据上题求:(2+1)(22+1)(24+1)(28+1)…(232+1)+1的个位数字.
解:原式=(2﹣1)(2+1)(22+1)(24+1)(28+1)…(232+1)+1
=(22﹣1)(22+1)(24+1)(28+1)…(232+1)+1
=(24﹣1)(24+1)(28+1)…(23