A:90x=60x−6
B:90x=60x+6
C:90x−6=60x
D:90x+6=60x
(Ⅰ)求函数f(x)的单调区间;
(Ⅱ)当a>0时,若f(x)≥0对任意的x∈R恒成立,求实数a的值;
(Ⅲ)求证: ln1+2×3(3−1)2+ln1+2×32(32−1)2+⋯+ln1+2×3n(3n−1)2<2 .
要使8□524≈8万,□里不能填( )