甲、乙两船从相距300km的A、B两地同时出发相向而行，甲船从A地顺流航行180km时与从B地逆流航行的乙船相遇，水流的速度为6km/h，若甲、乙两船在静水中的速度均为xkm/h，则求两船在静水中的速

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甲、乙两船从相距300km的A、B两地同时出发相向而行，甲船从A地顺流航行180km时与从B地逆流航行的乙船相遇，水流的速度为6km/h，若甲、乙两船在静水中的速度均为xkm/h，则求两船在静水中的速度可列方程为（）

A： $\frac{180}{x + 6}$ = $\frac{120}{x - 6}$

B： $\frac{180}{x - 6}$ = $\frac{120}{x + 6}$

C： $\frac{180}{x + 6}$ = $\frac{120}{x}$

D： $\frac{180}{x}$ = $\frac{120}{x - 6}$

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A

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