解:(Ⅰ)由ρ﹣2cosθ=0得C1:ρ2﹣2ρcosθ=0,
故x2+y2﹣2x=0,
消去参数得C2:2x﹣y﹣2m﹣1=0;
(Ⅱ)由(Ⅰ)知,C1是圆,C2是直线;
x2+y2﹣2x=0可化为(x﹣1)2+y2
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