①∠AOB+∠BOC=45。;② |BC| =2AB;
③ |OB|2 =10 |AB|2 ; ④ |OC|2 = 85|OB|2
已知{an}为等差数列,前n项和为Sn(n∈N+),{bn}是首项为2的等比数列,且公比大于0,b2+b3=12,b3=a4﹣2a1,S11=11b4.
(Ⅰ)求{an}和{bn}的通项公式;
(Ⅱ)求数列{a2nb2n﹣1}的前n项和(n∈N+).