丛菊两开他日泪，____ 。

增加：在缺词处加一个漏词符号（∧），并在其下面写出该加的词。

删除：把多余的词用斜线（\）划掉。

修改：在错的词下划一横线，并在该词下面写出修改后的词。

注意：

1). 每处错误及其修改均仅限一词；

2). 只允许修改10处，多者（从第11处起）不计分。

    As Christmas is coming, I plan to buy something for my parent. What I want to give back is a VIP card of a health club but neither of them is doing enough exercise. My father works very hardly as a teacher, spending most of his time at school. My mother loves reading and often bury herself in her books. Therefore, all of them should exercise more from now on.

    I want to give them this card to express my love and thanks for them. I hope that they will be able to get relaxing in the health club and make more friends here. At the same time, I hope that they can take care their health.

着力化解过剩产能，重点抓好钢铁、煤炭等困难行业去产能，坚持市场倒逼，坚决淘汰落后产能，有序退出过剩产能，积极稳妥处置”僵尸企业”。通过市场倒逼来化解过剩产能，其传导路径是（　　）

材料：将分式 $\frac{-x^4-x^2+3}{-x^2+1}$ 拆分成一个整式与一个分式（分子为整数）的和的形式．

解：由分母为﹣x²+1，可设﹣x⁴﹣x²+3=（﹣x²+1）（x²+a）+b则﹣x⁴﹣x²+3=（﹣x²+1）（x²+a）+b=﹣x⁴﹣ax²+x²+a+b=﹣x⁴﹣（a﹣1）x²+（a+b）

∵对应任意x，上述等式均成立，∴ $\{\begin{array}{c}a-1=1\\ a+b=3\end{array}$ ，∴a=2，b=1

∴ $\frac{-x^4-x^2+3}{-x^2+1}$ = $\frac{\left(-x^2+1\right)\left(x^2+2\right)+1}{-x^2+1}$ = $\frac{\left(-x^2+1\right)\left(x^2+2\right)}{-x^2+1}$ + $\frac{1}{-x^2+1}$ =x²+2+ $\frac{1}{-x^2+1}$ 这样，分式 $\frac{-x^4-x^2+3}{-x^2+1}$ 被拆分成了一个整式x²+2与一个分式 $\frac{1}{-x^2+1}$ 的和．

解答：