如图,在平行四边形ABCD和平行四边形AECF的顶点,D,E,F,B在一条直线上,则下列等式成立的是( )
A:AE=CE
B:CE=CF
C:DE=BF
D:DE=EF=BF
已知:3Cu+8HNO3=3Cu(NO3)2+2NO↑+4H2O,现把19.2g Cu放入足量的稀硝酸中,微热至Cu完全反应.求:
读图,完成下题
40+2= 70+3= 10+8= 80+0= 40+5=
3+90= 10+6= 30+2= 50+9= 9+80=
1+10= 8+80= 20+1= 20+3=
0+10= 18–8= 86–6= 68–8= 65–5= 55–50= 93–90= 35–5= 45–40= 75–70= 38–30= 27–20=
57–7= 37–7= 100–30= 66–6=
43–3= 94–90= 34–30= 89–9= 51–1=