分式方程 $\frac{2x}{x-1}+\frac{1}{1-x}=3$ 的解是____．

某班要从甲、乙两名同学中选拔出一人，代表班级参加学校的一分钟踢毽子体能素质比赛，在一段时间内的相同条件下，甲、乙两人进行了六场一分钟踢毽子的选拔测试，根据他们的成绩绘制出如图的统计表和不完整的折线统计图．

             甲、乙两人选拔测试成绩统计表

	甲成绩 （次/min）	乙成绩 （次/min）
第1场	87	87
第2场	94	98
第3场	91	87
第4场	85	89
第5场	91	100
第6场	92	85
中位数	91	n
平均数	m	91

并计算出乙同学六场选拔测试成绩的方差：

S_乙²= $\frac{{\left(87-91\right)}^2+{\left(98-91\right)}^2+{\left(87-91\right)}^2+{\left(89-91\right)}^2+{\left(100-91\right)}^2+{\left(85-91\right)}^2}{6}$ = $\frac{101}{3}$

阅读上面短文，然后判断句子正( A )误( B)。
     A man saw a boy standing beside a lake with a mirror (镜子).“Excuse me,” he said, “but could you tell me what you're doing?”
   “I'm fishing.”
   “With a mirror? Could you tell me how it works?”the man asked.
   “OK, but I want five dollars.”
     The man wanted to know the secret very much, so he handed the boy the money.“Now show me how it works,” he said. “Well”, the boy began, “you hold (拿) the mirror towards the water, and when a fish goes by, the sunlight in the mirror gives him a surprise. He stops and doesn't know what to do, and then you catch him at once. ”The man was surprised, “Can you really catch fish with the mirror? How many did you catch?”
   “You're the fifth today!” replied the boy.

已知向量$\overrightarrow{a}$=(m,n),$\overrightarrow{b}$=($\cos \theta ,\sin \theta$），其中$m,n,\theta \in R$，若$\left|\overrightarrow{a}\right|=4\left|\overrightarrow{b}\right|$，当$\overrightarrow{a}·\overrightarrow{b}<\lambda$恒成立时实数$\lambda$的取值范围是（   ）

函数f（x）= $\frac{1}{x}$ ﹣x的图象关于（   ）