如图,直线AB,CD相交于点O,OF平分∠AOE,OF⊥CD,垂足为O.
(1)写出图中所有与∠AOD互补的角;
(2)若∠AOE=120°,求∠BOD的度数.
解:(1)∵直线AB,CD相交于点O,
∴∠AOC和∠BOD与∠AOD互补,
∵OF平分∠AOE,
∴∠AOF=∠EOF,
∵OF⊥CD,
∴∠COF=∠DOF=90°,
∴∠DOE=∠ACO,
∴∠DOE也是∠AOD的补角,
∴与∠AOD互补的角有∠AOC,∠BOD,∠DOE;
(2)∵OF平分∠AOE,
∴∠AOF= 同类题1 Can you teach ________to play basketball?
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