如图,OABC是一张放在平面直角坐标系中的矩形纸片,O为原点,点A在x轴的正半轴上,OA=10,OC=8,在OC上取一点D,将纸片沿AD翻折,使点O落在BC边上的点E处,求直线DE的解析式._刷题宝

题干

如图,OABC是一张放在平面直角坐标系中的矩形纸片,O为原点,点A在x轴的正半轴上,OA=10,OC=8,在OC上取一点D,将纸片沿AD翻折,使点O落在BC边上的点E处,求直线DE的解析式.

上一题下一题 0.0难度选择题更新时间:2019-01-03 10:29:12

答案(点此获取答案解析）

解：依题意可知，折痕AD是四边形OAED的对称轴，
∴在Rt△ABE中，AE=AO=10，AB=8，BE= $\sqrt{A E^{2} - A B^{2}} = \sqrt{10^{}}$

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