甲乙两地相距360千米，一轮船往返于甲、乙两地之间，顺水行船用18小时，逆水行船用24小时，若设船在静水中的速度为x千米/时，水流速度为y千米/时，则下列方程组中正确的是(         )

A：$\left\{\begin{array}{c}18\left(x+y\right)=360\\ 24\left(x-y\right)=360\end{array}\right.$

B：$\left\{\begin{array}{c}18\left(x+y\right)=360\\ 24\left(x+y\right)=360\end{array}\right.$

C：$\left\{\begin{array}{c}18\left(x-y\right)=360\\ 24\left(x-y\right)=360\end{array}\right.$

D：$\left\{\begin{array}{c}18\left(x-y\right)=360\\ 24\left(x+y\right)=360\end{array}\right.$