题干

已知在25℃,101kPa下,lgC8H18(辛烷)燃烧生成二氧化碳和液态水时放出48.40kJ热量。表示上述反应的热化学方程式正确的是

A:C8H18(1)+22.5O2(g)=8CO2(g)+9H2O(g)△H=-48.40kJ·mol-1

B:C8H18(1)+22.5O2(g)=8CO2(g)+9H2O(1)△H=-5518kJ·mol-1

C:C8H18(1)+22.5O2(g)=8CO2(g)+9H2O(1)△H=+5518kJ·mol-1

D:C8H18(1)+22.5O2(g)=8CO2(g)+9H2O(1)△H=-48.40kJ·mol-1

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答案(点此获取答案解析)

B

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