已知函数f（x）= {2x,−1<x≤1f(x−2)+1,1<x≤3 ，则函数g（x）=f（f（x））﹣2在区间（﹣_刷题宝

题干

已知函数f（x）= {2x,−1<x≤1f(x−2)+1,1<x≤3 ，则函数g（x）=f（f（x））﹣2在区间（﹣1，3]上的零点个数是（）

A：1

B：2

C：3

D：4

上一题下一题 0.0难度选择题更新时间:2019-12-30 08:17:41

答案(点此获取答案解析）

C

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