已知函数f（x）= {kx+1(x≤0)log12x,(x＞0) ，则关于函数F（x）=f（f（x））的零点个数，正确的结论是_1．（写出你认为正确的所有结论的序号） ①_刷题宝

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已知函数f（x）= {kx+1(x≤0)log

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x,(x＞0) ，则关于函数F（x）=f（f（x））的零点个数，正确的结论是____．（写出你认为正确的所有结论的序号）

①k=0时，F（x）恰有一个零点．②k＜0时，F（x）恰有2个零点．

③k＞0时，F（x）恰有3个零点．④k＞0时，F（x）恰有4个零点．

上一题下一题 0.0难度选择题更新时间:2019-05-26 05:44:06

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