∴AC⊥PD.∵四边形ABCD是菱形,∴AC⊥BD,
又∵PD∩BD=D,AC⊥平面PBD.
而AC⊂平面EAC,∴平面EAC⊥平面PBD.
(Ⅱ)解:∵PD∥平面EAC,平面EAC∩平面PBD=OE,
∴PD∥OE,
∵O是BD中点
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