A:
B:
C:
D:
设函数,f(x)=|x﹣a|
(Ⅰ)当a=2,解不等式,f(x)≥5﹣|x﹣1|;
(Ⅱ)若f(x)≤1的解集为0,2,1m+12n=a(m>0,n>0),求证:m+2n≥4.