一辆汽车沿笔直的公路以10m/s的速度匀速行驶,现以0.6m/s2的加速度加速,10s后速度能达到多少?10s内的位移是多少?
解:根据速度时间关系知,10s汽车达到的速度为:
v=v0+at=10+0.6×10m/s=16m/s;
根据位移时间关系有:
x= v0t+12a
On getting the ____, they ____ the disaster-hit area.
—No, she isn't. She's than me.