集合A={x|x2﹣3x﹣10≤0},集合B={x|m+1≤x≤2m﹣1}.
(1)若B⊆A,求实数m的取值范围;
(2)当x∈R时,没有元素x使x∈A与x∈B同时成立,求实数m的取值范围.
解:因为x2﹣3x﹣10≤0,所以(x+2)(x﹣5)≤0,解得﹣2≤x≤5.所以A={x|﹣2≤x≤5}.
(1)当m+1>2m﹣1即m<2时,B=∅满足B⊆A;
当m+1≤2m﹣1即m≥2时,要使B⊆A成立,则m+1
Let's _____ the old man cross the road.
Information about a Robot
Name: Engkey Country: Korea
Job. A teacher Height: About ____.
Color: ____.
Abilities:
●Moves around the classrooms while speaking to students.
●____ to students.
●Dances to music by moving her ____.
Use: Be controlled by English teachers to teach English.
Good point: They needn't____.
4____320÷8;
614÷3____205;
619÷6____110;
730____17×29.