题干

定义:三角形三条内角平分线的交点叫做三角形的内心;

性质:内心到三角形三边的距离相等.

如图1,点 O△ABC的内心, ODABDOEBC 于E, OFCAF ,则有 OD=OE=OF=d .

问题:如何求 d 的值呢?

探究

上一题 下一题 0.0难度 选择题 更新时间:2011-03-24 10:15:40

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