若圆C与圆（x﹣2）²+（y+1）²=1关于原点对称，则圆C的方程为（　　）

A：${\left(x-2\right)}^2+{\left(y+1\right)}^2=1$

B：${\left(x+2\right)}^2+{\left(y-1\right)}^2=1$

C：${\left(x+2\right)}^2+{\left(y+1\right)}^2=1$

D：${\left(x-2\right)}^2+{\left(y-1\right)}^2=1$