有这样一道题，当a=2，b=﹣2时，求多项式：3a3b3﹣ 12 a2b+b2﹣3（a3b3﹣ 16 a2b﹣b2）﹣2b2﹣3的值，马虎做题时把a=2错抄成a=﹣2，王真没抄错题，但他们做出的结果却_刷题宝

题干

有这样一道题，当a=2，b=﹣2时，求多项式：

3a³b³﹣

1

2

a²b+b²﹣3（a³b³﹣

1

6

a²b﹣b²）﹣2b²﹣3的值，马虎做题时把a=2错抄成a=﹣2，王真没抄错题，但他们做出的结果却都一样，你知道这是怎么回事吗？说明理由．

上一题下一题 0.0难度选择题更新时间:2019-09-09 07:55:47

答案(点此获取答案解析）

解：原式=3a³b³﹣

1

2

a²b+b²﹣3a³b³+

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