题干

如图,∠DAB=∠EAC,AB=AE,AD=AC.求证:DE=BC.

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答案(点此获取答案解析)

证明:∵∠DAB=∠EAC,

∴∠DAB+∠BAE=∠EAC+∠BAE,

即:∠EAD=∠CAB

在△ACB和△ADE中:

{AB=AE

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