函数f（x）= x2+5x2+4 （x∈R）的最小值为_刷题宝

题干

函数f（x）=

x
2
+
5
x
2
+
4

（x∈R）的最小值为（）

A：2

B：3

C：2 $\sqrt{2}$

D：2.5

上一题下一题 0.0难度选择题更新时间:2012-04-12 08:36:16

答案(点此获取答案解析）

D

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