New York is one of (A)_______ (excite) cities in the world.
   You might want to do some shopping in New York. Fifth Avenue is probably New York’s most famous shopping street, but if you go, be prepared to “window shop” only. This is shopping for the rich. There are other, less expensive shopping areas（区域）nearby, and you’ll soon (B)come across famous stores such as Bloomingdales, Macy’s and FAO Schwartz.
   And if you’ve brought your rollerblades, then a visit to Central Park is a must. This is a large, open park right in the middle of Manhattan, but if you thought that people came here to relax, sits down for a few minutes and get away from the rush of New York life, then you’d be wrong. Nobody sits in Central Park: they run, jog（慢跑）, and most of all they rollerblade.
   When you leave New York, you might be tired, even poor and overweight, but the one thing you won’t be is bored!  

下列哪项不是解决基因歧视的正确方法（　　）

①向量 $\stackrel{\rightharpoonup }{a}$ ， $\stackrel{\rightharpoonup }{b}$ 不共线，则向量 $\stackrel{\rightharpoonup }{a}+\stackrel{\rightharpoonup }{b}$ 与向量 $\stackrel{\rightharpoonup }{a}-\stackrel{\rightharpoonup }{b}$ 一定不共线

②对任意向量 $\stackrel{\rightharpoonup }{a}$ ， $\stackrel{\rightharpoonup }{b}$ ，则 $\left|\stackrel{\rightharpoonup }{a}-\stackrel{\rightharpoonup }{b}|\ge |\right|\stackrel{\rightharpoonup }{a}|-|\stackrel{\rightharpoonup }{b}\left|\right|$ 恒成立

③在同一平面内，对两两均不共线的向量 $\stackrel{\rightharpoonup }{a}$ ， $\stackrel{\rightharpoonup }{b}$ ， $\stackrel{\rightharpoonup }{c}$ ，若给定单位向量 $\stackrel{\rightharpoonup }{b}$ 和正数 $\lambda$ ，总存在单位向量 $\stackrel{\rightharpoonup }{c}$ 和实数 $\mu$ ，使得 $\stackrel{\rightharpoonup }{a}=\lambda \stackrel{\rightharpoonup }{c}+\mu \stackrel{\rightharpoonup }{b}$

则正确的序号为（    ）