One upon a time, there were two fishermen who were good at fishing. One day, they went to a lake to1 . One of them 2 fishing alone by himself 3the other was an outgoing person who loved to 4 friends with different people.

    When the second fisherman found that some tourists at the lake couldn't catch any fish. He said to them“I will teach you how to do that. If you catch 10 fish, give me one. If you don't get 10,you 5 give me anything.”

    They felt like old friends at the first sight. Both sides come to a(n)6 immediately. After he finished teaching a group, he went to teach another, and 7 taught them some fishing skills.He asked one for every 10 fish the tourists 8 .

    At the 9 of the day, the fisherman who kindly helped others received a(n)10 basket of fish, and also got to know a large group of new friends. At the same time, he was respected（尊重）as a(n)11 .

    However,12 fisherman didn't have much fun. When the others circled around his camp, he became even more 13 . After fishing for a whole day alone, he looked into the 14 basket,and found he had far fewer fish than his friend.

    If we 15 others succeed, we get both success and friends.

下列城市被誉为花园城市的是（　　）

PE=y．

已知点P（x₀，y₀）和直线y=kx+b，则点P到直线y=kx+b的距离证明可用公式d= $\frac{\left|k{x}_0-y_0+b\right|}{\sqrt{1+k^2}}$ 计算．

例如：求点P（﹣1，2）到直线y=3x+7的距离．

解：因为直线y=3x+7，其中k=3，b=7．

所以点P（﹣1，2）到直线y=3x+7的距离为：d= $\frac{\left|k{x}_0-y_0+b\right|}{\sqrt{1+k^2}}$ = $\frac{\left|3\times (-1)-2+7\right|}{\sqrt{1+k^2}}$ = $\frac{2}{\sqrt{10}}$ = $\frac{\sqrt{10}}{5}$ ．

根据以上材料，解答下列问题：