- 基础理论
- 数据及数据库技术
- 人工智能
- 算法理论
- 算法实例
- 面向对象程序设计 VB开发工具
- 算法实例的程序实现
- 算法及算法的表示方法
- 多媒体理论
- 基础软件操作
- 算法软件操作
- 多媒体软件操作
- 网络技术应用
编写“数字序列”程序,实现如下功能:在文本框Text1中输入[100,500]范围内的整数,单击“生成”按钮Command1,在列表框List1中显示9个该序列的数字。数字序列的生成规则为:该项的数字+该数百位上的数字+该数十位上的数字+该数个位上的数字=下一项的数字,例如:365+3+6+5=379。小明编写了VB程序,运行的界面如图所示,程序代码如下:

(1)代码“Private Sub Command1_Click()”中的Command1_Click()是_________。
(单选,填字母:
(2)为实现上述功能,请在划线处填入合适的代码。
Private Sub Command1_Click( )
Dim n As Integer, i As Integer
Dim a As Integer,b As Integer
Dim c As Integer
List1.Clear
n = Val(Text1.Text)
If n >= 100 And n <= 500 Then
For i = 1 To 9
a = n \ 100
b = (n - 100 * a) \ 10
c = n Mod 10
_______________________
Next i
Else
List1.AddItem "输入数值有误"
End If

End Sub
(3)上述代码段中缺少了List1.AddItem Str(i)+"."+Str(n),此句代码应该加在_____(填字母)位置。
(4)若输入的数字为123,则List1中第三行为__________________。

(1)代码“Private Sub Command1_Click()”中的Command1_Click()是_________。
(单选,填字母:
A.对象名 | B.事件 | C.事件处理过程 | D.方法 ) |
Private Sub Command1_Click( )
Dim n As Integer, i As Integer
Dim a As Integer,b As Integer
Dim c As Integer
List1.Clear
n = Val(Text1.Text)
If n >= 100 And n <= 500 Then
For i = 1 To 9

a = n \ 100
b = (n - 100 * a) \ 10
c = n Mod 10
_______________________

Next i

Else
List1.AddItem "输入数值有误"
End If

End Sub
(3)上述代码段中缺少了List1.AddItem Str(i)+"."+Str(n),此句代码应该加在_____(填字母)位置。
(4)若输入的数字为123,则List1中第三行为__________________。
某VB程序段如下:
s=0
For i=2 To 5
For j=i To 5
If j Mod i=0 Then
a(j)=a(j)+1
s=s+a(j)
End If
Next j
Next i
数组a的初值均为0,上面程序段执行后,最终变量s的值为( )
s=0
For i=2 To 5
For j=i To 5
If j Mod i=0 Then
a(j)=a(j)+1
s=s+a(j)
End If
Next j
Next i
数组a的初值均为0,上面程序段执行后,最终变量s的值为( )
A.6 | B.5 | C.4 | D.3 |
某 VB 程序代码如下:
n=Val(Text1.Text)
sum=n
k=4
Do While n\k>0
sum=sum+n\k
n=n\k+n mod k
Loop
Text2.Text=Str(sum)
在文本框 Text1中输入10,执行该程序段后,文本框 Text2中显示的值是( )
n=Val(Text1.Text)
sum=n
k=4
Do While n\k>0
sum=sum+n\k
n=n\k+n mod k
Loop
Text2.Text=Str(sum)
在文本框 Text1中输入10,执行该程序段后,文本框 Text2中显示的值是( )
A.12 | B.13 | C.14 | D.16 |
有如下 Visual Basic 程序段:
s = 0
For k = To 5 s = s + k
Next k
该程序段运行后,循环体 s = s + k 被执行 10 次,则循环变量 k 的初值是( )
s = 0
For k = To 5 s = s + k
Next k
该程序段运行后,循环体 s = s + k 被执行 10 次,则循环变量 k 的初值是( )
A.14 | B.-5 | C.1 | D.-4 |
用计算机无法解决"打印所有素数"的问题,其原因是解决该问题的算法违背了算法特征中的( )
A.唯一性 | B.有穷性 | C.有0个或多个输入 | D.有输出 |
下列能表示"x 大于0 且 x 小于10"的Visual Basic表达式是( )
A.x > 0 Or x < 10 | B.x >= 0 And x < 10 |
C.x >= 0 And x <= 10 | D.x > 0 And x < 10 |
(加试题)某VB程序段如下:
s = ""
For i = 1 To 5
a(i) = 0
Next i
For i = 2 To 5
For j = i To 5
If j Mod i = 0 Then a(j) = 1 - a(j)
Next j
Next i
For i = 1 To 5
If a(i) = 1 Then s = s + Str(i)
Next i
Text1.Text = s
运行该程序段后,Text1中显示的内容为
s = ""
For i = 1 To 5
a(i) = 0
Next i
For i = 2 To 5
For j = i To 5
If j Mod i = 0 Then a(j) = 1 - a(j)
Next j
Next i
For i = 1 To 5
If a(i) = 1 Then s = s + Str(i)
Next i
Text1.Text = s
运行该程序段后,Text1中显示的内容为
A.2 3 5 | B.1 4 | C.2 5 | D.2 3 4 |
(加试题)小明编写了一个统计字符串中数字字符串之和的VB程序(如字符串“ab12.3cd34ef9”,中数字字符串之和为58:12+3+34+9),运行界面如图所示。在文本框Text1中输入字符串s,单击“统计”按钮Command1,在Label3中输出统计结果。

实现上述功能的VB程序代码如下,但划线处代码有错,请改正。
Private Sub Command1_Click()
Dim s As String, ch As String
Dim ch2 As String, sum As Double
Dim n As Integer, i As Integer
s = Text1.Text
n = Len(s)
ch = Mid(s, i, 1)
If ch >= "0" And ch <= "9" Then
j = i
ch2 = Mid(s, j, 1)
Do While ch2 >= "0" And ch2 <= "9"
j = j + 1
ch2 = Mid(s, j, 1)
Loop
sum = sum + Val(Mid(s, i, j – i - 1)) '②_____________
i = j
End If
i = i + 1
Loop
Label3.Caption = Str(sum)
End Sub

实现上述功能的VB程序代码如下,但划线处代码有错,请改正。
Private Sub Command1_Click()
Dim s As String, ch As String
Dim ch2 As String, sum As Double
Dim n As Integer, i As Integer
s = Text1.Text
n = Len(s)
i = 1: sum = 0
Do While i < n '①_____________ch = Mid(s, i, 1)
If ch >= "0" And ch <= "9" Then
j = i
ch2 = Mid(s, j, 1)
Do While ch2 >= "0" And ch2 <= "9"
j = j + 1
ch2 = Mid(s, j, 1)
Loop
sum = sum + Val(Mid(s, i, j – i - 1)) '②_____________
i = j
End If
i = i + 1
Loop
Label3.Caption = Str(sum)
End Sub
(加试题)异或的数学符号为“⊕”,其运算法则相当于不带进位的二进制加法:0⊕0=0,1⊕0=1,0⊕1=1,1⊕1=0(即符号两侧数值相同时,计算结果为0;数值不同时为1)。
如果要对两个十进制数进行异或运算,可以按以下步骤进行:
① 先将要进行异或运算的两个十进制数分别转换为二进制;
② 对两个二进制数按位进行异或运算;例:(101101)2⊕(111)2=(101010)2
③ 再把步骤②中的运算结果转换为十进制,该十进制数即为运算结果。
小明编写了一个VB程序来模拟上述运算过程,程序功能如下:在文本框Text1和Text2中分别输入要参加异或运算的十进制数,单击计算按钮Command1,程序对输入的两个数进行异或运算,并将运算结果显示在文本框Text3中,程序运行界面如图所示。
(2)实现上述功能的VB程序如下。请在划线处填入合适的代码。
Private Sub Command1_Click()
Dim a As Integer, b As Integer, c As Integer
Dim a1 As String, b1 As String
Dim lena1 As Integer, lenb1 As Integer, i As Integer
Dim result As String
a = Val(Text1.Text)
b = Val(Text2.Text)
If a > b Then
c = a: a = b: b = c
End If
result = ""
a1 = DtoB(a): b1 = DtoB(b)
lena1 = Len(a1): lenb1 = Len(b1)
i = 1
Do While i <= lena1
If Mid(a1, lena1 - i + 1, 1) = Mid(b1, lenb1 - i + 1, 1) Then
result = "0" + result
Else
result = "1" + result
End If
i = i + 1
Loop
result =①_____
Text3.Text = BtoD(result)
End Sub
Public Function DtoB(x As Integer) As String
Dim remainder As String
DtoB = ""
Do While x > 0
remainder = CStr(x Mod 2) '如:CStr(3 Mod 2)的值为"1"
DtoB = remainder + DtoB
②________
Loop
End Function
Public Function BtoD(x As String) As Integer
Dim i As Integer
BtoD = 0
For i = 1 To Len(x)
BtoD =③________+ Val(Mid(x, i, 1))
Next i
End Function
如果要对两个十进制数进行异或运算,可以按以下步骤进行:
① 先将要进行异或运算的两个十进制数分别转换为二进制;
② 对两个二进制数按位进行异或运算;例:(101101)2⊕(111)2=(101010)2
③ 再把步骤②中的运算结果转换为十进制,该十进制数即为运算结果。
小明编写了一个VB程序来模拟上述运算过程,程序功能如下:在文本框Text1和Text2中分别输入要参加异或运算的十进制数,单击计算按钮Command1,程序对输入的两个数进行异或运算,并将运算结果显示在文本框Text3中,程序运行界面如图所示。
(2)实现上述功能的VB程序如下。请在划线处填入合适的代码。
Private Sub Command1_Click()
Dim a As Integer, b As Integer, c As Integer
Dim a1 As String, b1 As String
Dim lena1 As Integer, lenb1 As Integer, i As Integer
Dim result As String
a = Val(Text1.Text)
b = Val(Text2.Text)
If a > b Then
c = a: a = b: b = c
End If
result = ""
a1 = DtoB(a): b1 = DtoB(b)
lena1 = Len(a1): lenb1 = Len(b1)
i = 1
Do While i <= lena1
If Mid(a1, lena1 - i + 1, 1) = Mid(b1, lenb1 - i + 1, 1) Then
result = "0" + result
Else
result = "1" + result
End If
i = i + 1
Loop
result =①_____
Text3.Text = BtoD(result)
End Sub
Public Function DtoB(x As Integer) As String
Dim remainder As String
DtoB = ""
Do While x > 0
remainder = CStr(x Mod 2) '如:CStr(3 Mod 2)的值为"1"
DtoB = remainder + DtoB
②________
Loop
End Function
Public Function BtoD(x As String) As Integer
Dim i As Integer
BtoD = 0
For i = 1 To Len(x)
BtoD =③________+ Val(Mid(x, i, 1))
Next i
End Function