1.单选题- (共19题)
2Ag+O2↑+2X↑，则X的化学式是| A．上述反应都属于置换反应 |
| B．反应中铜元素在固体中质量分数逐渐增大 |
| C．都可采用相同的实验装置 |
| D．反应后产物中的氧都来自于氧化铜中的氧 |
A. CO+ CuO
Cu + CO2↑B. Ca(OH)2+CO2→CaCO3↓+H2O
C. 2H2O
H2↑+O2↑D. Na2CO3+H2SO4→NaSO4+H2O+CO2↑
| A．NaOH、CuSO4、Ca（OH）2、KNO3 |
| B．Na2CO3、HCl、BaCl2、AgNO3 |
| C．HCl、KOH、H2SO4、MgCl2 |
| D．NaCl、Fe2（SO4）3、KCl、Ba（OH）2 |
2Fe + SiO2,该反应中作还原剂的是| A．金刚石和石墨的物理性质不同，是因为构成物质的原子不同 |
| B．水结成冰，体积发生变化，说明水分子的大小发生了变化 |
| C．氧气需加压后贮存钢瓶中，说明氧分子间有间隙 |
| D．双氧水分解能生成氧气，说明双氧水分子中含有氧分子 |
| A．稀有气体制霓虹灯——稀有气体化学性质稳定 |
| B．盐酸用于除铁锈——盐酸能与碱性氧化物反应 |
| C．一氧化碳可用于冶炼金属——一氧化碳有可燃性 |
| D．熟石灰用来改良酸性土壤——熟石灰微溶于水 |
A． 向一定量的氢氧化钠溶液中滴加稀盐酸 |
B． 一定量的石灰石与足量的稀盐酸反应 |
C． 向一定量盐酸和硫酸钠的混合溶液中，滴加氢氧化钡溶液 |
D． 相等质量的镁和铁分别与足量的10%稀硫酸反应 |
| A．N2中混有O 2（通过红热的木炭） |
| B．烧碱中混有纯碱（加适量稀盐酸、蒸发） |
| C．HCl溶液中混有H2SO4（加适量的硝酸钡溶液并过滤） |
| D．CaO中混有CaCO3（高温煅烧） |
收集氧气
称量氢氧化钠固体
测定某溶液的pH
加热液体2.选择题- (共23题)
—Well, you don't need to read it because there is _____in it.
Trees are useful to man in three very important ways. The first important way is that they provide man {#blank#}1{#/blank#} food, wood and other products(产品). Trees provide man and animals with food to live {#blank#}2{#/blank#} the earth. It's not easy {#blank#}3{#/blank#} man to live on the earth without trees.
The {#blank#}4{#/blank#} important way is that trees give us shade(树荫). On a hot summer day, people can have {#blank#}5{#/blank#}rest under the shade of a tree after they have walked a long way. You can imagine（想象） {#blank#}6{#/blank#} important the shade of a tree is to man and animals.
The third important {#blank#}7{#/blank#} is that trees help to prevent droughts（干旱）and floods. However, in many parts of the world, man has {#blank#}8{#/blank#} realized the third important way. He has cut {#blank#}9{#/blank#}trees in large numbers.{#blank#}10{#/blank#} the end, he finds that he has lost his best friends.
A: You must be really excited about leaving for America tomorrow, Li Ping!
B: Yeah.{#blank#}1{#/blank#}
A: Nervous about what?
B:I don't know many of the customs and manners in the USA.{#blank#}2{#/blank#}
A: Sure.
B:{#blank#}3{#/blank#}
A: Well, it's important to be on time when you're invited for dinner.{#blank#}4{#/blank#}Americans expect their guests to be on time.
B: Then how long may I stay there?
A:{#blank#}5{#/blank#}Or you seem to have come only for the meal. When your friends seem to be getting tired and running out of things, it's time to leave. The next day, call or write a thank-you note to say how much you enjoyed the evening.
A. It's good to stay at home for you. B. After the meal, don't leave at once. C. Could you give me a hand? D. What rules do they have in America? E. But I'm a bit nervous. F. You're supposed to leave before the meal. G. It's impolite to arrive late. |
The aim (目的) of students who come to school is to study. But studying requires (需要) a right way, or you waste either the time or the money. The following are the ways of studying.
The best time for reading is morning, because in the morning, the air is fresh and the mind is clear. For that reason, we can get good results (结果).
In studying we must have patience (耐心). If we have not known a text well, we must read it again. We shouldn't read the next one till we have understood the first one.
When we are studying, we must put our hearts into the book, or we can get nothing from the book while we are reading.
We must always ask “whys”. If it is not well understood, write it down and ask our teachers, parents, or friends. In any possible way, we must know it completely and what we've leaned can be used well and made better.
Though there are many ways for studying, yet the above mentioned (提到的) will be quite enough if we can keep them in heart and do so.
3.填空题- (共4题)
①空气中体积分数为78%的气体的化学式是 。
②活性炭用于去除冰箱中异味，是利用活性炭的 性。
③在炒菜时，若将食盐或食盐水溅到煤气的火焰上，火焰就呈 色。
④农业上尿素是一种常用的氮肥，化学式是CO（NH2）2。它由 种元素组成，尿素的摩尔质量为 。
①实验1：写出该反应的化学方程式 。
②实验2：该实验证明水是由 组成的化合物。
③CO2与NaOH溶液反应无明显现象，为证明其反应，设计实验3。可观察到的实验现象是塑料瓶变瘪了，其原理是利用 。有同学却对此提出质疑，他认为上述实验不严谨，其理由是 ，要得到科学严谨的结论，仍利用该装置，补做的对比实验是将氢氧化钠溶液换成 ，与加入氢氧化钠溶液的实验现象进行对比。
若用检验生成物的方法证明二氧化碳与氢氧化钠发生反应，所用的试剂是 。
①通过实验Ⅰ和Ⅱ可比较出镁和铁的金属活动性强弱。你认为他们依据的实验现象是 。写出实验Ⅰ中反应的化学方程式： 。
②通过观察到实验Ⅲ的现象可得出的结论是 。
③上述三个实验不能够得出四种金属的活动性顺序。探究小组在上述实验的基础上，补充了一个实验（如图所示），实现了探究目的。他们的实验：金属X、Y溶液分别是 。
| 温度/℃ | 0 | 20 | 40 | 80 | 100 | |
| 溶解度/ g/100g水 | Ca（OH）2 | 0．173 | 0．165 | 0．121 | 0．094 | 0．076 |
| NaOH | 31 | 91 | 111 | 313 | 336 | |
①从上表数据可以看出，氢氧化钙的溶解度随温度的升高而________________。
②40℃时，将20g水配成氢氧化钠饱和溶液，需氢氧化钠的质量为______克。若将40℃时422克的氢氧化钠饱和溶液稀释为20%的溶液，需加水__________克。
③80℃时含有Ca（OH）2和NaOH两种溶质的饱和溶液，若要从中得到较纯净的NaOH晶体，应采取的物理方法是________________。
④现有20℃时Ca（OH）2的饱和溶液（甲溶液），向其中加入一定量CaO后得到的溶液（乙溶液），此时甲乙两杯溶液中_________。
A甲的溶质的质量分数与乙的相同
B甲的溶质的质量分数大于乙的
C甲的溶质的质量小于乙的
D甲、乙都是饱和溶液
4.实验题- (共1题)
-
【1】题量占比
单选题:(19道)
选择题:(23道)
填空题:(4道)
实验题:(1道)
-
【2】：难度分析
1星难题：0
2星难题：0
3星难题：0
4星难题：3
5星难题：0
6星难题：11
7星难题：0
8星难题：9
9星难题：1