1.单选题- (共6题)
A.200米指位移 |
B.19秒79为时间间隔 |
C.博尔特撞线时可以看成质点 |
D.博尔特夺冠是因为他的加速度最大 |

A.![]() |
B.![]() |
C.![]() |
D.![]() |
A. 5∶4 B. 4∶5 C. 3∶4 D. 4∶3
A.运动员将垒球拋出后,垒球的运动状态仍在变化,垒球仍为受力物体,但施力物体不是运动员 |
B.用手压弹簧,手先给弹簧一个作用,弹簧压缩后再反过来给手一个作用 |
C.甲物体对乙物体施加了力,则甲物体本身可能不受力的作用 |
D.重心就是物体各部分所受重力的合力的等效作用点,实际存在于物体上 |
A. 40 m/N B. 40 N/m
C. 200 m/N D. 200 N/m
2.选择题- (共2题)
Gabi Rizea only discovered his talent for woodcarving three years ago, and has since put{#blank#}1{#/blank#} to good use, saving dozens of old tree stumps (树桩) from {#blank#}2{#/blank#} (remove) by turning them into impressive works of art.
Rizea became a woodcarver{#blank#}3{#/blank#} (complete) by accident. Three years ago, after buying himself a new chainsaw (链锯), he{#blank#}4{#/blank#} (start) “playing” with it on a block of wood. He tried carving a human face into the wood, and to his surprise, it turned out pretty good. Today, he is so good at woodcarving that his home city allows him to work his magic on old tree stumps and so far about 40 works of art{#blank#}5{#/blank#}(create) in the local parks.
“In 99% of the cases, the wood just doesn't match my ideas,” he said in an interview. “I first have to remove all the rotten parts, and sometimes{#blank#}6{#/blank#} is left isn't enough for my designs.”
Following his recent rise to fame, Rizea has been asked by many{#blank#}7{#/blank#} (city), including the capital of Romania to transform their old tree trunks {#blank#}8{#/blank#} works of art. He promised to honor their requests, but he will never repeat any of the artworks{#blank#}9{#/blank#} (find) in his home city.
In spite of his obvious talent, the Romanian {#blank#}10{#/blank#} (art) recently got into art school in order to fully master woodcarving.
下列关于《中华人民共和国环境保护法》的说法正确的是( )
①是我国环境保护的基本法
②在我国环境保护法律体系中占有核心地位
③我国已形成以环境保护法为基础,以宪法为主体的环境保护法律体系
④环境保护法为保护和治理环境提供了法律依据
3.多选题- (共2题)

A.汽车的初速度为4 m/s | B.汽车的加速度大小为0.5 m/s2 |
C.汽车第4 s末的速度为2 m/s | D.汽车前10 s内的位移为15 m |

A.在t=0 时,甲车在乙车前7.5m |
B.在t=1s时,甲车在乙车后 |
C.两车另一次并排行驶的时刻是t=2s |
D.甲、乙车两次并排行驶的位置之间沿公路方向的距离为40m |
4.解答题- (共4题)
(1)乙车追上甲车之前,两车之间的最大距离sm;
(2)经过多少时间t,乙车追上甲车;
(3)乙车一追上甲车,乙车就立即刹车,减速过程加速度大小a′=6 m/s2,则再经过多少时间t′,甲、乙两车再次相遇。
5.实验题- (共2题)


(1)部分实验步骤如下:
A.测量完毕,关闭电源,取出纸带。 |
B.接通电源,待打点计时器工作稳定后放开小车。 |
C.将小车停靠在打点计时器附近,小车尾部与纸带相连。 |
D.把打点计时器固定在平板上,让纸带穿过限位孔。 |
(2)图(b)中标出的相邻两计数点的时间间隔T=________s。
(3)计数点5对应的瞬时速度大小计算式为v5=________。
(4)为了充分利用记录数据,减小误差,小车加速度大小的计算式应为a=________。

砝码的质量![]() | 0.05 | 0.10 | 0.15 | 0.20 | 0.25 |
滑动摩擦力![]() | 2.15 | 2.36 | 2.55 | ![]() | 2.93 |

回答下列问题:
(1)


(2)在图(c)的坐标纸上补齐未画出的数据点并绘出

(3)








(4)取



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【1】题量占比
单选题:(6道)
选择题:(2道)
多选题:(2道)
解答题:(4道)
实验题:(2道)
-
【2】:难度分析
1星难题:0
2星难题:0
3星难题:0
4星难题:1
5星难题:0
6星难题:7
7星难题:0
8星难题:6
9星难题:0