江西省上饶县中学2016-2017学年高二下学第13周物理周练试题

适用年级:高二
试卷号:92405

试卷类型:专题练习
试卷考试时间:2017/10/4

1.选择题(共2题)

1.看图写数.

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写作{#blank#}2{#/blank#}

2.

完形填空

    One day before my final exam, my dad gave me a gift. It completely changed my life.

    On that day I had a 1  with my friends and it was a difficult time with my studies. I was unhappy. Then I noticed the gift. I 2 it and saw a DVD inside. Its name was “THE SECRET”. However, I was in no mood (心情) to watch it. I sat down to study, but the 3  in my life—the fight, the sleepless nights and my poor health...everything came to my mind. I wanted an answer but I wondered 4  there was any. Just then, I saw the DVD again. Maybe it would be helpful. I   5 my DVD player. I had no words to describe the feelings I experienced while watching it. The moving (动人的) stories of human beings made me so moved that I wouldn't 6  any of them.

    Thanks to my father's gift “THE SECRET”, I discovered 7. Everybody has difficulties in their lives. The important thing is that you should be 8 enough to face them. Now I have started 9 my studies and my friends. And I'm in good health, too. I often hear people say, “Wow! 10  perfect life you have!”

2.单选题(共1题)

3.
一列简谐横波沿x轴传播.t=0时刻的波形如图甲所示,此时质点P正沿y轴负方向运动,其振动图像如图乙所示.则该波的传播方向和波速分别是
A.沿x轴负方向,60m/sB.沿x轴正方向,60m/s
C.沿x轴负方向,30m/sD.沿x轴正方向,30m/s

3.多选题(共4题)

4.
某同学漂浮在海面上,虽然水面波正平稳地以的速率向着海滩传播,但他并不向海滩靠近。该同学发现从第1个波峰到第10个波峰通过身下的时间间隔为。下列说法正确的是(   )
A.水面波是一种机械波
B.该水面波的频率为
C.该水面波的波长为
D.水面波没有将该同学推向岸边,是因为波传播时能量不会传递出去
E.水面波没有将该同学推向岸边,是因为波传播时振动的质点并不随波迁移
5.
如图所示,实线和虚线分别表示振幅、频率均相同的两列波的波峰和波谷,此刻,M是波峰与波峰相遇点,下列说法中正确的是
A.该时刻质点O正处在平衡位置
B.P、N两点始终处于平衡位置
C.点M到两波源的距离之差一定是波长的整数倍
D.从该时刻起,经过周期,质点M到达平衡位置
6.
在均匀介质中坐标原点O处有一波源做简谐运动,其表达式为,它在介质中形成的简谐横波沿x轴正方向传播,某时刻波刚好传播到x=12 m处,波形图象如图所示,则
A.此后再经6 s该波传播到x=24 m处
B.M点在此后第3 s末的振动方向沿y轴正方向
C.波源开始振动时的运动方向沿y轴负方向
D.此后M点第一次到达y=-3 m处所需时间是2 s
7.
两列振动方向相同、振幅分别为A1和A2的相干简谐横波相遇。下列说法正确的是()
A.波峰与波谷相遇处质点的振幅为|A1-A2|
B.波峰与波峰相遇处质点离开平衡位置的位移始终为A1+A2
C.波峰与波谷相遇处质点的位移总是小于波峰与波峰相遇处质点的位移
D.波峰与波峰相遇处质点的振幅一定大于波峰与波谷相遇处质点的振幅

4.填空题(共1题)

8.
一列简谐横波在t=0时刻的波形如图所示,质点P此时刻沿-y运动,经过0.1 s第一次到达平衡位置,波速为5 m/s,则下列说法正确的是__。
A.该波沿x轴负方向传播   
B.Q点的振幅比P点的振幅大
C.P点的横坐标为x=2.5 m   
D.Q点的振动方程为y=5cos t cm
E.x=3.5 m处的质点与P点振动的位移始终相反

5.解答题(共1题)

9.
如图所示为一列简谐横波在t=0时刻的图象.此时质点P的运动方向沿y轴负方向,且当t=0.55s时质点P恰好第3次到达y轴正方向最大位移处.问:

(1)该简谐横波的波速v的大小和方向如何?
(2)从t=0至t=1.2s,质点Q运动的路程L是多少?
(3)当t=1.2s时,质点Q相对于平衡位置的位移x的大小是多少?
试卷分析
  • 【1】题量占比

    选择题:(2道)

    单选题:(1道)

    多选题:(4道)

    填空题:(1道)

    解答题:(1道)

  • 【2】:难度分析

    1星难题:0

    2星难题:0

    3星难题:0

    4星难题:0

    5星难题:0

    6星难题:4

    7星难题:0

    8星难题:3

    9星难题:0